arrow_backBack to Study Resources

Quiz Chapter 7: Quantum Physics

10 questions · Form 5 Physics Bab 7: Quantum Physics

10 questions · plays in fullscreen

Full Question List & Answer Key

Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.

1. Calculate the energy of a single photon of blue light with a frequency of 6.0 × 10¹⁴ Hz. (Planck's constant h = 6.63 × 10⁻³⁴ J s)

  1. 3.98 × 10⁻¹⁹ J
  2. 1.11 × 10⁻⁴⁷ J
  3. 3.98 × 10⁻²⁷ J
  4. 1.80 × 10⁻¹⁹ J
Show answer

Answer: A

E = h × f = (6.63 × 10⁻³⁴ J s) × (6.0 × 10¹⁴ Hz) = 3.978 × 10⁻¹⁹ J ≈ 3.98 × 10⁻¹⁹ J.

2. Why could classical wave theory NOT explain the photoelectric effect?

  1. Classical theory predicted that electron emission required continuous light wave energy buildup over time
  2. Classical theory predicted that light travels faster in dense media
  3. Classical theory predicted that electrons carry positive charges
  4. Classical theory stated that photons have zero momentum
Show answer

Answer: A

Wave theory assumed energy spread continuously over wave fronts, predicting time delays for dim light, whereas experiments proved emission is instantaneous.

3. In a photoelectric experiment, the stopping potential V_s is measured to be 1.5 V. What is the maximum kinetic energy of the photoelectrons in Joules? (e = 1.6 × 10⁻¹⁹ C)

  1. 2.4 × 10⁻¹⁹ J
  2. 1.07 × 10⁻¹⁹ J
  3. 1.50 J
  4. 3.84 × 10⁻¹⁹ J
Show answer

Answer: A

K_max = e × V_s = (1.6 × 10⁻¹⁹ C) × 1.5 V = 2.4 × 10⁻¹⁹ J.

4. What is the threshold frequency (f₀) of a metal?

  1. The maximum frequency of light that causes reflection
  2. The minimum frequency of light required to emit photoelectrons from a metal surface
  3. The frequency at which photoelectrons reach zero kinetic energy in a vacuum
  4. The frequency of light produced by thermal heating
Show answer

Answer: B

Threshold frequency (f₀) is the minimum photon frequency needed to overcome the metal's work function (Φ = hf₀).

5. A solar panel in a satellite converts light energy directly into electrical energy using the:

  1. Thermionic emission process
  2. Photoelectric effect
  3. Electromagnetic induction process
  4. Nuclear fusion process
Show answer

Answer: B

Solar panels utilize photovoltaic solar cells operating on the photoelectric effect to convert solar photons directly into electric current.

6. Light of photon energy 5.0 × 10⁻¹⁹ J strikes a metal surface with a work function of 3.2 × 10⁻¹⁹ J. What is the maximum kinetic energy of the emitted photoelectrons?

  1. 8.2 × 10⁻¹⁹ J
  2. 1.8 × 10⁻¹⁹ J
  3. 1.56 × 10⁻¹⁹ J
  4. 3.2 × 10⁻¹⁹ J
Show answer

Answer: B

K_max = E_photon - Work Function = 5.0 × 10⁻¹⁹ J - 3.2 × 10⁻¹⁹ J = 1.8 × 10⁻¹⁹ J.

7. What happens to the stopping potential (V_s) if light of a higher frequency is used in a photoelectric setup?

  1. Stopping potential decreases
  2. Stopping potential increases
  3. Stopping potential remains unchanged
  4. Stopping potential drops to zero
Show answer

Answer: B

Higher photon frequency yields higher maximum kinetic energy (K_max), requiring a larger stopping potential (e V_s = K_max) to halt emitted photoelectrons.

8. If the stopping potential for photoelectrons emitted from a metal plate is 2.0 V, what is the maximum velocity of the photoelectrons? (m_e = 9.1 × 10⁻³¹ kg, e = 1.6 × 10⁻¹⁹ C)

  1. 8.39 × 10⁵ m s⁻¹
  2. 7.04 × 10¹¹ m s⁻¹
  3. 3.51 × 10⁵ m s⁻¹
  4. 1.20 × 10⁶ m s⁻¹
Show answer

Answer: A

K_max = e V_s = 1.6 × 10⁻¹⁹ × 2.0 = 3.2 × 10⁻¹⁹ J. Then 0.5 × m × v² = 3.2 × 10⁻¹⁹ => v = √[ 2 × 3.2 × 10⁻¹⁹9.1 × 10⁻³¹ ] = 8.39 × 10⁵ m s⁻¹.

9. If light of frequency f below the threshold frequency (f < f₀) shines on a metal surface, what happens?

  1. Photoelectrons are emitted very slowly after a long time delay
  2. No photoelectrons are emitted regardless of light intensity
  3. Photoelectrons are emitted with maximum kinetic energy
  4. The metal surface instantly melts
Show answer

Answer: B

If f < f₀, individual photons lack sufficient energy to overcome the work function, so zero photoelectrons are emitted regardless of brightness.

10. What is the gradient of a K_max against frequency (f) graph for any photoelectric metal surface?

  1. Work function (Φ)
  2. Planck's constant (h)
  3. Threshold frequency (f₀)
  4. Electron mass (m_e)
Show answer

Answer: B

Comparing K_max = hf - Φ to y = mx + c shows the gradient m equals Planck's constant h for all metals.

Sponsored