10 questions · Form 5 Physics Bab 3: Electricity
10 questions · plays in fullscreen
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. An electric motor takes in 500 W of electrical power and delivers 400 W of mechanical output power. What is the efficiency of the motor?
Answer: A
Efficiency = (Output Power / Input Power) × 100% = (400 W500 W) × 100% = 80%.
2. An air conditioner rated at 1.5 kW is operated for 8 hours daily. How many units (kWh) of electricity are consumed by the appliance in a 30-day month?
Answer: A
Energy = Power (kW) × time (hours) = 1.5 kW × (8 h/day × 30 days) = 1.5 kW × 240 h = 360 kWh.
3. Three identical 10 Ω resistors are connected in SERIES to a 15 V battery. What is the potential difference across ONE of the resistors?
Answer: B
Total resistance R = 10 + 10 + 10 = 30 Ω. Current I = 1530 = 0.5 A. Voltage across one resistor V = I × R_i = 0.5 A × 10 Ω = 5 V.
4. An electric heater rated 240 V, 1200 W is connected to a 240 V mains supply. What is the operating current of the heater?
Answer: A
P = V × I => I = PV = 1200 W240 V = 5 A.
5. Two resistors of 6 Ω and 12 Ω are connected in PARALLEL across a 12 V power supply. What is the total current supplied by the source?
Answer: A
Effective resistance 1R = 16 + 112 = 312 => R = 4 Ω. Total current I = VR = 12 V4 Ω = 3 A.
6. A current of 2.5 A flows through a bulb for 4 minutes. What total electric charge passes through the bulb?
Answer: B
Q = I × t = 2.5 A × (4 × 60 s) = 2.5 A × 240 s = 600 C.
7. A uniform wire of resistance 12 Ω is stretched uniformly until its length doubles while its volume remains constant. What is the new resistance of the wire?
Answer: B
When length doubles (l' = 2l), cross-sectional area halves (A' = A2) to keep volume constant. New R' = ρ(2l / (A2)) = 4 ρ(lA) = 4 × 12 = 48 Ω.
8. Superconductors are unique materials that exhibit:
Answer: B
Superconductors lose all electrical resistance (R = 0) when cooled below their specific critical temperature (Tc).
9. If 120 J of electrical work is done to transfer 15 C of charge across a resistor, what is the potential difference across the resistor?
Answer: B
V = WQ = 120 J15 C = 8 V.
10. Why is electrical energy transmitted at very high voltages over long distances in national grid systems?
Answer: B
Transmitting at high voltage lowers the current (I = PV). Since power loss in cables is P_loss = I²R, lower current drastically reduces thermal energy loss.