10 questions · Form 5 Mathematics Bab 1: Variation
If x ∝ y^n and x = 54 when y = 3 with k = 2, find the value of n.
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. If x ∝ y^n and x = 54 when y = 3 with k = 2, find the value of n.
Answer: B
x = k y^n => 54 = 2(3^n) => 27 = 3^n => 3³ = 3^n => n = 3.
2. Which of the following graphs represents y varying directly as x?
Answer: A
Direct variation y = kx is a linear relationship passing through the origin (0,0).
3. The time T taken to complete a job varies inversely as the number of workers W. If 6 workers take 10 hours, how many hours will 15 workers take?
Answer: A
T = kW => 10 = k6 => k = 60. Equation: T = 60W. For W = 15 => T = 6015 = 4 hours.
4. If y varies inversely as the square root of x, and y = 5 when x = 16, calculate the value of k.
Answer: B
y = k / √x => 5 = k / √16 => 5 = k4 => k = 20.
5. The table below shows some values of p and q. If p varies directly as the square of q, find the equation connecting p and q if p = 18 when q = 3.
Answer: A
p ∝ q² => p = kq². Substituting p = 18, q = 3 => 18 = k(3²) => 18 = 9k => k = 2. Thus, p = 2q².
6. Variable A varies directly as B1/3). When B = 27, A = 6. Calculate A when B = 64.
Answer: B
A = k B1/3) => 6 = k (271/3)) => 6 = 3k => k = 2. When B = 64 => A = 2 (641/3)) = 2(4) = 8.
7. If y varies directly as x, and y = 12 when x = 3, find the constant of variation, k.
Answer: A
Since y ∝ x, y = kx. Substituting y = 12 and x = 3 gives 12 = 3k, so k = 4.
8. If p ∝ qr and p = 4 when q = 8 and r = 6, find the value of r when p = 12 and q = 16.
Answer: B
p = kq/r => 4 = k86 => k = 3. Equation: p = 3qr. When p = 12, q = 16 => 12 = 316r => 12 = 48r => r = 4.
9. Given that y varies inversely as (x + 2). If y = 3 when x = 2, find x when y = 2.
Answer: A
y = kx + 2 => 3 = k2 + 2 => k = 12. When y = 2 => 2 = 12x + 2 => 2x + 4 = 12 => 2x = 8 => x = 4.
10. The volume V of a cylinder varies directly as its height h and the square of its radius r. If V = 154 cm³ when r = 7 cm and h = 1, find constant k (use π ≈ 227).
Answer: C
V = k r² h => 154 = k (7²)(1) => 154 = 49k => k = 15449 = 227.