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Quiz Chapter 3: Integration

10 questions · Form 5 Additional Mathematics Bab 3: Integration

Question 1 of 10Score: 0

Find the indefinite integral ∫ (3x² - 4x + 5) dx.

Full Question List & Answer Key

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1. Find the indefinite integral ∫ (3x² - 4x + 5) dx.

  1. x³ - 2x² + 5x + c
  2. 3x³ - 4x² + 5x + c
  3. 6x - 4 + c
  4. x³ - 4x² + 5x + c
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Answer: A

∫ (3x² - 4x + 5) dx = 3(x³/3) - 4(x²/2) + 5x + c = x³ - 2x² + 5x + c.

2. Evaluate ∫₀⁴ (1 / √(2x + 1)) dx.

  1. 2
  2. 3
  3. 1
  4. 4
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Answer: A

∫₀⁴ (2x + 1)⁻¹/² dx = [(2x + 1)¹/² / (2 × 12)]₀⁴ = [√(2x + 1)]₀⁴ = √9 - √1 = 3 - 1 = 2.

3. Evaluate ∫ (2x + 1)³ dx.

  1. (2x + 1)⁴ / 4 + c
  2. (2x + 1)⁴ / 8 + c
  3. 3(2x + 1)² + c
  4. (2x + 1)⁴ / 2 + c
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Answer: B

Using ∫ (ax + b)ⁿ dx = (ax + b)ⁿ⁺¹ / [a(n + 1)] + c: ∫ (2x + 1)³ dx = (2x + 1)⁴ / [2(4)] + c = (2x + 1)⁴ / 8 + c.

4. Find the area bounded by the curve x = y² - 4 and the y-axis from y = 0 to y = 2.

  1. 163 units²
  2. 83 units²
  3. 4 units²
  4. 123 units²
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Answer: A

Area = |∫₀² (y² - 4) dy| = |[y³/3 - 4y]₀²| = |(83 - 8) - 0| = |-163| = 163 units².

5. Find the volume of revolution generated when the region bounded by the curve y = √x, the x-axis, and x = 4 is rotated 360° about the x-axis.

  1. 8π units³
  2. 16π units³
  3. 32π units³
  4. 4π units³
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Answer: A

V = π ∫₀⁴ y² dx = π ∫₀⁴ (√x)² dx = π ∫₀⁴ x dx = π [x²/2]₀⁴ = π (162 - 0) = 8π units³.

6. Given that ∫₁⁴ f(x) dx = 7, evaluate ∫₁⁴ [2f(x) + 3] dx.

  1. 23
  2. 17
  3. 20
  4. 14
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Answer: A

∫₁⁴ [2f(x) + 3] dx = 2 ∫₁⁴ f(x) dx + ∫₁⁴ 3 dx = 2(7) + [3x]₁⁴ = 14 + (12 - 3) = 14 + 9 = 23.

7. Given that ∫₂⁵ g(x) dx = 6 and ∫₅⁸ g(x) dx = -2, find the value of ∫₂⁸ g(x) dx.

  1. 8
  2. -12
  3. 4
  4. -4
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Answer: C

Using property: ∫₂⁸ g(x) dx = ∫₂⁵ g(x) dx + ∫₅⁸ g(x) dx = 6 + (-2) = 4.

8. Find the volume generated when the line y = 2x from x = 0 to x = 3 is revolved 360° about the x-axis.

  1. 36π units³
  2. 18π units³
  3. 72π units³
  4. 24π units³
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Answer: A

V = π ∫₀³ y² dx = π ∫₀³ (2x)² dx = π ∫₀³ 4x² dx = π [4x³/3]₀³ = π [4273] = 36π units³.

9. Find ∫ (6x³ - 2) dx.

  1. -3x² - 2x + c
  2. -18x⁴ - 2x + c
  3. 3x² - 2x + c
  4. -3x⁴ - 2x + c
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Answer: A

∫ (6x⁻³ - 2) dx = 6(x⁻²/-2) - 2x + c = -3x⁻² - 2x + c = -3x² - 2x + c.

10. If d/dx [f(x)] = 3x² + 2x, find f(x) given that f(1) = 4.

  1. f(x) = x³ + x² + 2
  2. f(x) = x³ + x² + 4
  3. f(x) = 6x + 2 - 4
  4. f(x) = x³ + x²
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Answer: A

f(x) = ∫ (3x² + 2x) dx = x³ + x² + c. f(1) = 1³ + 1² + c = 4 => 2 + c = 4 => c = 2. f(x) = x³ + x² + 2.

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