Quiz Chapter 8: Kinematics of Linear Motion

1. When an object moves with uniform velocity, what is its acceleration?

1. a = 0
2. a = v
3. a > 0
4. a = 9.8

2. How is acceleration obtained from a displacement function s(t)?

1. By differentiating s(t) twice with respect to t: d²s/dt²
2. By integrating s(t) with respect to t
3. By taking ds/dt
4. By dividing s(t) by t²

3. What is the difference between displacement and total distance?

1. Displacement is vector (can be negative) representing net position; distance is scalar (always ≥ 0) representing total path length
2. Displacement is always greater than distance
3. Distance depends on direction, displacement does not
4. Displacement is measured in ms⁻¹, distance in meters

4. If displacement s = -15 m, what does this indicate about the position of the particle?

1. It is 15 meters to the left (negative side) of fixed point O
2. It is 15 meters to the right of fixed point O
3. It has traveled a total distance of -15 meters
4. It is moving backwards at 15 ms⁻¹

5. What is the condition for a particle to be instantaneously at rest?

1. v = 0
2. s = 0
3. a = 0
4. t = 0

6. Given v = 3t² - 12, find the displacement during the time interval 0 ≤ t ≤ 2 s.

1. -16 m
2. 16 m
3. -24 m
4. 8 m

7. Given acceleration a = 4t - 8 and the initial velocity is 3 ms⁻¹, find the velocity function v(t).

1. v = 2t² - 8t + 3
2. v = 4t² - 8t + 3
3. v = 2t² - 8
4. v = 2t² - 8t

8. An object passes through fixed point O when t = 0. What is its displacement at t = 0?

1. s = 0
2. s = v
3. s = 1
4. s = a

9. Find the acceleration of a particle at t = 2 s if its velocity is v = 2t³ - 5t.

1. 19 ms⁻²
2. 24 ms⁻²
3. 11 ms⁻²
4. 16 ms⁻²

10. Given acceleration a = 6 ms⁻². If initial velocity is 2 ms⁻¹, find the velocity after 4 seconds.

1. 26 ms⁻¹
2. 24 ms⁻¹
3. 20 ms⁻¹
4. 12 ms⁻¹