10 questions · Form 4 Additional Mathematics Bab 1: Quadratic Functions
If α and β are roots of 2x² - 6x + 3 = 0, find the value of α + β.
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. If α and β are roots of 2x² - 6x + 3 = 0, find the value of α + β.
Answer: B
Sum of roots α + β = -ba = --62 = 62 = 3.
2. If α and β are the roots of x² - 5x + 2 = 0, evaluate α² + β².
Answer: A
SOR α + β = 5, POR αβ = 2. Use identity: α² + β² = (α + β)² - 2αβ = (5)² - 2(2) = 25 - 4 = 21.
3. Find the roots of the quadratic equation 2x² - 5x - 3 = 0.
Answer: A
Factorising gives (2x + 1)(x - 3) = 0 => 2x + 1 = 0 or x - 3 = 0 => x = -12 or x = 3.
4. Find the quadratic equation whose roots are reciprocal to the roots of 3x² - 7x + 2 = 0.
Answer: A
Roots of original equation: SOR = 73, POR = 23. For reciprocal roots 1/α and 1/β: New SOR = (α+β)/(αβ) = (73)/(23) = 72. New POR = 1/(αβ) = 32. Equation: x² - (72)x + 32 = 0 => 2x² - 7x + 3 = 0.
5. Find the minimum value of the quadratic function f(x) = 2(x + 1)² - 9.
Answer: B
In vertex form f(x) = a(x - h)² + k with a = 2 > 0, the minimum value is given directly by k, which is -9.
6. Solve the quadratic inequality x² - 4x - 5 < 0.
Answer: B
Factorise: (x + 1)(x - 5) < 0. Critical values are x = -1 and x = 5. For '< 0', the solution is between the roots: -1 < x < 5.
7. Find the range of values of k for which the equation x² + 4x + k = 0 has two distinct real roots.
Answer: A
Two distinct roots require b² - 4ac > 0 => (4)² - 4(1)(k) > 0 => 16 - 4k > 0 => 4k < 16 => k < 4.
8. The graph of f(x) = ax² + bx + c does NOT intersect the x-axis. Which statement must be TRUE?
Answer: D
No intersection with the x-axis means the quadratic equation f(x) = 0 has no real roots, so b² - 4ac < 0.
9. State the y-intercept of the quadratic graph f(x) = -2(x - 1)² + 8.
Answer: B
y-intercept occurs when x = 0: f(0) = -2(0 - 1)² + 8 = -2(1) + 8 = 6. Thus, y-intercept is (0, 6).
10. The quadratic function f(x) = -(x - 3)² + 7 has a turning point at (h, k). State the coordinates and nature of the turning point.
Answer: C
Since a = -1 < 0, the graph is maximum shaped (∩). From f(x) = a(x - h)² + k, vertex is (h, k) = (3, 7).