10 questions · Form 3 Science Bab 7: Energy and Power
10 questions · plays in fullscreen
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. A worker pushes a crate with a constant horizontal force of $50 N$ across a smooth floor over a distance of $4 m$. How much work is done by the worker?
Answer: C
Work $W = F × s = 50 N × 4 m = 200 J$.
2. Calculate the gravitational potential energy possessed by a $2 kg$ book rested on a shelf $3 m$ above the floor ($g = 10 m s-2$).
Answer: D
Gravitational potential energy $E_p = mgh = 2 × 10 × 3 = 60 J$.
3. What is the S.I. unit for measuring Work ($W$)?
Answer: A
Work is measured in Joules (J), which is equivalent to Newton-metres (N m).
4. An electric motor takes 4 seconds to perform 800 J of work. What is the power output of the motor?
Answer: D
Power $P = Wt = 800 J4 s = 200 W$.
5. A simple pendulum swings back and forth between points A, B, and C (where B is the lowest point). At which position is its kinetic energy at a MAXIMUM?
Answer: B
At the lowest position (B), gravitational potential energy is converted entirely into kinetic energy, reaching maximum speed.
6. Using conservation of energy, calculate the velocity of a $0.5 kg$ ball dropped from a height of $5 m$ just before hitting the floor ($g = 10 m s-2$).
Answer: A
$mgh = 12 m v2 arrow v = √2gh = √2 × 10 × 5 = √100 = 10 m s-1$.
7. A sports car of mass $1000 kg$ travels at a constant velocity of $20 m s-1$. Find its kinetic energy.
Answer: B
$E_k = 12 m v2 = 12 × 1000 × (20)2 = 500 × 400 = 200,000 J$ (or $200 kJ$).
8. A student weighing $450 N$ climbs a staircase of vertical height $4 m$ in $6 seconds$. What is the useful power generated by the student?
Answer: B
Work $W = F × s = 450 N × 4 m = 1800 J$. Power $P = 18006 = 300 W$.
9. In which of the following scenarios is NO work done according to physics definition?
Answer: B
Work requires displacement in the direction of applied force ($W = F × s$). Since displacement is zero ($s = 0$), no work is done.
10. A crane lifts a $500 kg$ load vertically upwards through a height of $10 m$ in $10 seconds$. Calculate the power generated by the crane (taking $g = 10 m s-2$).
Answer: B
Work $W = mgh = 500 × 10 × 10 = 50000 J$. Power $P = Wt = 5000010 = 5000 W$ (or $5 kW$).