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Quiz Chapter 2: Standard Form

10 questions · Form 3 Mathematics Bab 2: Standard Form

Question 1 of 10Score: 0

How many significant figures are there in 0.005040?

Full Question List & Answer Key

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1. How many significant figures are there in 0.005040?

  1. 6
  2. 4
  3. 3
  4. 5
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Answer: B

Leading zeros (0.00) are not significant. The digits 5, 0, 4, and the trailing zero 0 are significant, giving 4 s.f.

2. Find the value of (3.0 × 10⁴)² and state the answer in standard form.

  1. 9.0 × 10⁸
  2. 6.0 × 10⁸
  3. 9.0 × 10¹⁶
  4. 9.0 × 10⁶
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Answer: A

(3.0)² × (10⁴)² = 9.0 × 10⁴ˣ² = 9.0 × 10⁸.

3. Calculate (2 × 10⁴) × (3 × 10⁻⁶).

  1. 6 × 10⁻²
  2. 6 × 10⁻²⁴
  3. 5 × 10⁻²
  4. 6 × 10⁻¹⁰
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Answer: A

(2 × 3) × 10⁴⁺⁽⁻⁶⁾ = 6 × 10⁻².

4. A rectangular land has length 4 × 10³ m and width 2.5 × 10² m. Find the area of the land in m² in standard form.

  1. 1.0 × 10⁶
  2. 10 × 10⁵
  3. 1.0 × 10⁵
  4. 6.5 × 10⁵
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Answer: A

Area = length × width = (4 × 10³) × (2.5 × 10²) = (4 × 2.5) × 10³⁺² = 10 × 10⁵ = 1.0 × 10⁶ m².

5. Calculate (8 × 10⁻³) ÷ (4 × 10⁻⁷).

  1. 2 × 10⁻¹⁰
  2. 2 × 10⁴
  3. 2 × 10⁻⁴
  4. 2 × 10²¹
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Answer: B

(8 ÷ 4) × 10⁻³⁻⁽⁻⁷⁾ = 2 × 10⁻³⁺⁷ = 2 × 10⁴.

6. Evaluate (1.2 × 10³) × (5 × 10⁴) and state the answer in standard form.

  1. 6.0 × 10¹²
  2. 6.0 × 10⁷
  3. 60 × 10⁶
  4. 6.0 × 10⁸
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Answer: B

(1.2 × 5) × 10³⁺⁴ = 6.0 × 10⁷.

7. Round 49,960 to 3 significant figures.

  1. 50,000
  2. 49,900
  3. 50,0
  4. 49,960
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Answer: A

Target position is the second 9. Next digit is 6 (≥ 5), rounding up gives 50,000 (which represents 3 s.f. in this context).

8. Calculate 6.2 × 10⁵ - 4.1 × 10⁴.

  1. 2.1 × 10⁵
  2. 5.79 × 10⁴
  3. 2.1 × 10¹
  4. 5.79 × 10⁵
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Answer: D

6.2 × 10⁵ - 0.41 × 10⁵ = (6.2 - 0.41) × 10⁵ = 5.79 × 10⁵.

9. How many significant figures does the number 300.00 have?

  1. 1
  2. 3
  3. 5
  4. 2
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Answer: C

Trailing zeros after a decimal point are significant. All 5 digits (3, 0, 0, ., 0, 0) are significant.

10. If 0.0000072 = 7.2 × 10ⁿ, find the value of n.

  1. -6
  2. -5
  3. 6
  4. 5
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Answer: A

Moving decimal 6 places to the right gives n = -6.

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