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Quiz Chapter 2: Standard Form

10 questions · Form 3 Mathematics Bab 2: Standard Form

10 questions · plays in fullscreen

Full Question List & Answer Key

Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.

1. Calculate (2 × 10⁴) × (3 × 10⁻⁶).

  1. 6 × 10⁻²
  2. 6 × 10⁻²⁴
  3. 5 × 10⁻²
  4. 6 × 10⁻¹⁰
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Answer: A

(2 × 3) × 10⁴⁺⁽⁻⁶⁾ = 6 × 10⁻².

2. Calculate (8 × 10⁻³) ÷ (4 × 10⁻⁷).

  1. 2 × 10⁻¹⁰
  2. 2 × 10⁴
  3. 2 × 10⁻⁴
  4. 2 × 10²¹
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Answer: B

(8 ÷ 4) × 10⁻³⁻⁽⁻⁷⁾ = 2 × 10⁻³⁺⁷ = 2 × 10⁴.

3. Calculate 3.4 × 10⁴ + 2.5 × 10⁴.

  1. 5.9 × 10⁸
  2. 5.9 × 10⁴
  3. 5.9 × 10¹
  4. 59 × 10³
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Answer: B

(3.4 + 2.5) × 10⁴ = 5.9 × 10⁴.

4. A rectangular land has length 4 × 10³ m and width 2.5 × 10² m. Find the area of the land in m² in standard form.

  1. 1.0 × 10⁶
  2. 10 × 10⁵
  3. 1.0 × 10⁵
  4. 6.5 × 10⁵
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Answer: A

Area = length × width = (4 × 10³) × (2.5 × 10²) = (4 × 2.5) × 10³⁺² = 10 × 10⁵ = 1.0 × 10⁶ m².

5. Express 0.0000407 in standard form.

  1. 4.07 × 10⁻⁵
  2. 4.07 × 10⁵
  3. 40.7 × 10⁻⁶
  4. 4.07 × 10⁻⁴
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Answer: A

Move the decimal point 5 places to the right: 0.0000407 = 4.07 × 10⁻⁵.

6. Find the value of (3.0 × 10⁴)² and state the answer in standard form.

  1. 9.0 × 10⁸
  2. 6.0 × 10⁸
  3. 9.0 × 10¹⁶
  4. 9.0 × 10⁶
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Answer: A

(3.0)² × (10⁴)² = 9.0 × 10⁴ˣ² = 9.0 × 10⁸.

7. How many significant figures does the number 300.00 have?

  1. 1
  2. 3
  3. 5
  4. 2
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Answer: C

Trailing zeros after a decimal point are significant. All 5 digits (3, 0, 0, ., 0, 0) are significant.

8. Express 583,000 in standard form.

  1. 58.3 × 10⁴
  2. 5.83 × 10⁻⁵
  3. 5.83 × 10⁵
  4. 5.83 × 10⁶
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Answer: C

Move the decimal point 5 places to the left: 583,000 = 5.83 × 10⁵.

9. The mass of a water molecule is 3 × 10⁻²³ g. Calculate the mass of 4 × 10²¹ water molecules.

  1. 1.2 × 10⁻² g
  2. 1.2 × 10⁻1 g
  3. 12 g
  4. 1.2 × 10¹ g
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Answer: B

Total mass = (3 × 10⁻²³) × (4 × 10²¹) = 12 × 10⁻² = 1.2 × 10⁻¹ g.

10. Simplify 0.00012 ÷ (3 × 10⁻²).

  1. 4 × 10⁻³
  2. 4 × 10⁻²
  3. 4 × 10⁻⁶
  4. 0.4 × 10⁻³
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Answer: A

0.00012 = 1.2 × 10⁻⁴. (1.2 × 10⁻⁴) ÷ (3 × 10⁻²) = (1.2 ÷ 3) × 10⁻⁴⁻⁽⁻²⁾ = 0.4 × 10⁻² = 4 × 10⁻³.

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