10 questions · Form 2 Mathematics Bab 2: Factorisation and Algebraic Fractions
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Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. Simplify the expression: (2x3) + (x4).
Answer: B
Find the LCM of 3 and 4, which is 12: (2x × 412) + (x × 312) = 8x12 + 3x12 = 11x12.
2. What is the HCF of 12a²b and 18ab²?
Answer: C
HCF of 12 and 18 is 6. HCF of a²b and ab² is ab. Thus, HCF = 6ab.
3. Expand and simplify: (x + 5)(x - 5) + 25.
Answer: C
Expand (x + 5)(x - 5) to get x² - 25. Then x² - 25 + 25 = x².
4. What is the expanded form of (3a - 2b)²?
Answer: C
Using identity (x - y)² = x² - 2xy + y²: (3a)² - 2(3a)(2b) + (2b)² = 9a² - 12ab + 4b².
5. Simplify: (4mn) ÷ (2m² / 3n).
Answer: A
Change division to multiplication by reciprocal: (4mn) × (3n2m²) = 12mn2m²n = 6m.
6. Simplify the multiplication: (3x4y) × (8y² / 9x²).
Answer: A
Cancel common factors: (39) × (84) × (xx²) × (y²/y) = (13) × 2 × (1x) × y = 2y3x.
7. Factorise 2x² + 5x + 3.
Answer: B
Using cross-multiplication: (2x + 3)(x + 1) = 2x² + 2x + 3x + 3 = 2x² + 5x + 3.
8. Factorise 5p + 5q - ap - aq completely.
Answer: C
Group terms: 5(p + q) - a(p + q) = (5 - a)(p + q).
9. Factorise completely: 3x² - 12.
Answer: B
First factor out 3: 3(x² - 4). Then apply difference of squares: 3(x + 2)(x - 2).
10. Expand the expression -3x(2x - 5).
Answer: B
Multiply -3x by each term inside the bracket: (-3x)(2x) + (-3x)(-5) = -6x² + 15x.