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Chapter 3: Integration
Form 5 Additional Mathematics Bab 3: Integration
3.1 Integration as the Inverse of Differentiation
Integration is the reverse process of differentiation.
(p.83)
If d/dx[f(x)] = f′(x), then ∫ f′(x) dx = f(x).
(p.83)
3.2 Indefinite Integral
∫ a dx = ax + c (a, c constants).
(p.85)
∫ ax
n
dx = ax
n+1
/(n + 1) + c, n ≠ −1.
(p.85)
Steps: add 1 to the index of x, divide by the new index, add the constant c.
(p.85)
The constant c is the constant of integration, since differentiating gives the same dy/dx for different constants.
(p.86)
∫ [f(x) ± g(x)] dx = ∫ f(x) dx ± ∫ g(x) dx; ∫ ax
n
dx = a ∫ x
n
dx.
(p.86)
∫ (ax + b)
n
dx = (ax + b)
n+1
/ [a(n + 1)] + c, n ≠ −1.
(p.88)
Substitution method: let u = ax + b, so dx = du/a.
(p.89)
Given the gradient function dy/dx = f(x), the equation of the curve is y = ∫ f(x) dx.
(p.90)
Find c by substituting a known point (x, y) into the integrated equation.
(p.90)
3.3 Definite Integral
∫
a
b
f(x) dx = [g(x)]
a
b
= g(b) − g(a).
(p.92)
∫
a
a
f(x) dx = 0.
(p.94)
∫
a
b
f(x) dx = −∫
b
a
f(x) dx.
(p.94)
∫
a
b
kf(x) dx = k∫
a
b
f(x) dx.
(p.94)
∫
a
b
f(x) dx + ∫
b
c
f(x) dx = ∫
a
c
f(x) dx.
(p.94)
∫
a
b
[f(x) ± g(x)] dx = ∫
a
b
f(x) dx ± ∫
a
b
g(x) dx.
(p.94)
Area of a Region
As the number of thin rectangles increases, their total area approaches the actual area under the curve.
(p.96)
Area under the curve = lim
δx→0
Σ y
i
δx = ∫
a
b
y dx.
(p.96)
Region below the x-axis gives a negative integral; above gives a positive integral; the actual area is always positive.
(p.97)
If a curve crosses the x-axis, find the regions above and below separately and add their positive areas.
(p.98)
Area between the curve and the y-axis: A = ∫
a
b
x dy.
(p.99)
Region to the right of the y-axis gives a positive integral; to the left gives a negative integral.
(p.99)
Area between a curve y = g(x) and a line y = f(x) = ∫
a
b
[upper − lower] dx.
(p.102)
To find where a line and a curve intersect, substitute one equation into the other.
(p.103)
Area between two curves = ∫ (upper curve − lower curve) dx.
(p.104)
Volume of Revolution
A solid is generated when a region is revolved through 360° about an axis.
(p.105)
About the x-axis: V = ∫
a
b
πy
2
dx.
(p.107)
About the y-axis: V = ∫
a
b
πx
2
dy.
(p.107)
The generated volume is always positive.
(p.106)
For a region between a line and a curve, subtract the two generated volumes (V
1
− V
2
).
(p.109)
3.4 Applications of Integration
Integration is used to find areas, volumes and quantities from rates of change (e.g. growth of a bacteria colony, dA/dt).
(p.111)
For a parabolic bowl y = ax
2
, substitute a known point to find a, then use ∫πx
2
dy for the internal volume.
(p.111)
Total quantity from a rate = ∫ (rate) dt over the given time interval.
(p.112)
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