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Chapter 2: Differentiation

Form 5 Additional Mathematics Bab 2: Differentiation

2.1 Limit and Its Relation to Differentiation

  • When x approaches a (x ≠ a) and f(x) approaches L, the limit is written limx→a f(x) = L. (p.31)
  • If direct substitution gives 0/0 (indeterminate form), the limit cannot be found directly. (p.31)
  • Methods to find a limit: direct substitution, factorisation, rationalising the numerator or denominator. (p.31)
  • Rationalise by multiplying by the conjugate, using (a − b)(a + b) = a2 − b2. (p.32)
  • First derivative by first principles: dy/dx = limδx→0 δy/δx = limδx→0 [f(x + δx) − f(x)]/δx. (p.35)
  • Gradient of the curve at a point = gradient of the tangent = value of lim δy/δx. (p.35)
  • dy/dx is a single symbol for the limit of δy/δx as δx → 0; it is not dy divided by dx. (p.35)
  • Steps for first principles: take points A(x, y) and B(x + δx, y + δy); find δy = f(x + δx) − f(x); form δy/δx; take the limit as δx → 0. (p.36)

2.2 The First Derivative

  • If y = axn, then dy/dx = anxn−1 (a constant, n integer). (p.38)
  • If n = 1, dy/dx = a; if n = 0, dy/dx = 0. (p.38)
  • Gradient function f′(x) is a function; the gradient at a given point is a numeric value. (p.40)
  • d/dx[f(x) ± g(x)] = d/dx[f(x)] ± d/dx[g(x)] (differentiate each term separately). (p.40)
  • Chain rule: if y = g(u) and u = h(x), dy/dx = dy/du × du/dx. (p.42)
  • For y = un: d/dx(un) = nun−1 du/dx. (p.43)
  • Product rule: d/dx(uv) = u dv/dx + v du/dx. (p.44)
  • d/dx(uv) ≠ (du/dx)(dv/dx). (p.44)
  • Quotient rule: d/dx(u/v) = (v du/dx − u dv/dx)/v2, v ≠ 0. (p.45)

2.3 The Second Derivative

  • The second derivative is d2y/dx2 = d/dx(dy/dx), also written f″(x). (p.49)

2.4 Application of Differentiation

  • Gradient of tangent f′(a) < 0: tangent slants to the left (negative gradient). (p.51)
  • f′(a) = 0: tangent is horizontal (zero gradient). (p.51)
  • f′(a) > 0: tangent slants to the right (positive gradient). (p.51)
  • Line through P(x1, y1) with gradient m: y − y1 = m(x − x1). (p.53)
  • Equation of tangent at P(a, f(a)): y − f(a) = f′(a)(x − a). (p.53)
  • Equation of normal: y − f(a) = −[1/f′(a)](x − a), because m1m2 = −1. (p.53)

Turning Points and Their Nature

  • A stationary point occurs when dy/dx = 0. (p.58)
  • If dy/dx changes from positive to negative as x increases through a: maximum point. (p.58)
  • If dy/dx changes from negative to positive: minimum point. (p.58)
  • If dy/dx does not change sign: point of inflection (not a turning point). (p.58)
  • A stationary point is a turning point only if it is a maximum or minimum point. (p.58)
  • Second derivative test: dy/dx = 0 and d2y/dx2 < 0 gives a maximum point. (p.60)
  • dy/dx = 0 and d2y/dx2 > 0 gives a minimum point. (p.61)
  • If d2y/dx2 = 0, use the tangent-sketching (sign of gradient) method. (p.62)

Maximum and Minimum Problems

  • Method: express the quantity in one variable, solve dA/dr = 0, then use the second derivative to decide maximum or minimum. (p.63)
  • Volume of a cylinder V = πr2h; use it to eliminate h and form the surface-area function. (p.64)

Rates of Change of Related Quantities

  • If x and y change with time t and y = f(x): dy/dt = dy/dx × dx/dt (chain rule). (p.66)
  • A negative rate of change means the quantity is decreasing. (p.67)
  • For related-rate problems, use similar triangles to relate variables, e.g. r/5 = h/12 in the cone problem. (p.68)
  • Sphere: V = (4/3)πr3, so dV/dr = 4πr2. (p.69)

Small Changes and Approximations

  • δy/δx ≈ dy/dx for small δx, so δy ≈ (dy/dx) × δx. (p.71)
  • δy > 0: small increase in y; δy < 0: small decrease in y. (p.71)
  • f(x + δx) ≈ y + (dy/dx)δx, i.e. f(x) + f′(x)δx. (p.71)
  • Percentage change in x = (δx/x) × 100%; in y = (δy/y) × 100%. (p.72)
  • Small-change problems use δy ≈ (dy/dx)δx with the relevant formula (e.g. V = 4/3 πr3). (p.74)
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