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Chapter 4: Indices, Surds and Logarithms

Form 4 Additional Mathematics Bab 4: Indices, Surds and Logarithms

4.1 Laws of Indices

  • am × an = am+n; am ÷ an = am−n; (am)n = amn. (p.vii)
  • An algebraic expression involving indices is simplified using the laws of indices. (p.90)
  • If am = an then m = n; if am = bm then a = b (a > 0, a ≠ 1). Express both sides in the same base. (p.92)

4.2 Laws of Surds

  • Rational numbers can be written as a/b (b ≠ 0), including recurring decimals. Irrational numbers cannot be converted to fractions. (p.96)
  • A surd is a number in root form that cannot be simplified to a rational number; surds have non-recurring infinite decimals. For example √2 is a surd but √4 = 2 is not. (p.97)
  • Recurring decimals are converted to fractions by multiplying by a suitable power of 10 and subtracting. (p.98)
  • For a > 0, b > 0: √a × √b = √(ab) and √a ÷ √b = √(a/b). (p.100)
  • Simplify surds by extracting the largest perfect square factor, e.g. √18 = 3√2. (p.101)
  • Surds with the same irrational factor are similar surds and can be added or subtracted. (p.103)
  • Rationalising the denominator: multiply numerator and denominator by the conjugate surd. Conjugate of m√a + n√b is m√a − n√b. (p.104)
  • √a × √a = a, and (a − √b)(a + √b) = a2 − b. (p.104)

4.3 Laws of Logarithms

  • loga N = x ⇔ N = ax, where a > 0 and a ≠ 1. (p.110)
  • loga 1 = 0 and loga a = 1. loga N is defined only if N > 0. (p.110)
  • Common logarithm is base 10 (log10 a = lg a). If log10 N = x then antilog x = N. (p.110)
  • If f : x → ax then f−1 : x → loga x. (p.111)
  • Product law: loga xy = loga x + loga y. (p.114)
  • Division law: loga (x/y) = loga x − loga y. (p.114)
  • Power law: loga xn = n loga x. (p.114)
  • Change of base: loga b = logc b / logc a; in particular loga b = 1 / logb a. (p.117)
  • Natural logarithm: ln a = loge a with e ≈ 2.7182. ln e = 1, ln ex = x, eln x = x. (p.117)
  • Equations like 3x = 70 that cannot be written in the same base are solved by taking logarithms of both sides. (p.119)

4.4 Applications

  • Growth/decay models (e.g. A = 1000 × 20.2n) are solved by substituting values or using logarithms to find the time. (p.122)
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